3/4x-2=3-2/3x решите уравнение ! заранее

Question

Алгебра: 3/4x-2=3-2/3x решите уравнение ! заранее

zellen04 · Accepted Answer

2)y=sin²x+sinx x=0⇒y=0 y=0⇒sin²x+sinx=0⇒sinx(sinx+1)=0⇒ sinx=0⇒x=πn U sinx=-1⇒x=-π/2+πn (0;0),(πn;0),(-π/2+πn;0) y=cosx-cos2x-sin3x x=0⇒y=1-1-0=0 y=0⇒cosx-cos2x-sin3x=0⇒2sin3x/2sinx/2-2sin3x/2cos3x/2)=2sin3x/2(sinx/2-cos3x/2)=0 sin3x/2=0⇒3x/2=πn⇒x=2πn/3 sinx/2-cos3x/2=0⇒sinx/2-sin(π/2-3x/2)=0⇒-2sin(x/2-π/4)cos(x+π/4)=0 sin(x/2-π/4)=0⇒x/2-π/4=πn⇒x/2=π/4+πn⇒x=π/2+2πn cos(x+π/4)=0⇒x+π/4=π/2+πn⇒x=π/4+πn (0;0),(2πn/3 ;0),(π/2+2πn;0,(π/4+πn;0) 3.1)2-2sin²x-sinx-2 0 2sin²x+sinx 0 sinx=a 2a²+a 0⇒a(2a+1)...

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