Question

(х-1)^2+2(x-1)+1=x1 докажите тождество,

Answer 1

$(x-1)^2+2(x-1)+1=x1$

$x^2-2x+1+2x-2+1=x$

$x^{2}+0=x$

$x^{2} =x$

$x^{2} -x=0$

$x(x-1)=0$

$x=0$
$x-1=0$

$x_{1} =0$
$x_{2} =1$