2Na+2C2H5OH=2C2H5ONa+H2
2C6H5OH + 2Na = 2C6H5ONa + H2
2C2H5OH+Br2=2C2H5OBr+H2
c6h5oh + 3br2 = c6h2br3oh + 3hbr
n(C6H2Br3OH)=9.93/331=0.03моль
n(C6H5OH)=n(c6h2br3oh)=0.03моль
n(H2 фенол)=0.0581/2=0.015моль
n(H2 общее)=0.896/22.4=0.04моль
n(H2 этанол)=0.04-0.015=0.025моль
2n(H2 этанол)=n(C2H5OH)=2*0.025=0.05моль
m(C2H5OH)=0.05*46=2.3г
m(C6H5OH)=0.03*94=2.82г
m(смеси)=2.3+2.82=5.12г
w(C2H5OH)=2.3/5.12*100%=44.92%
пропанол
Объяснение: