239/93Np-239/94Pu 152/62Sm-148/60Nd 111/46Pd-111/47Ag - id1433667920230510 от Nightfury1012552 10.05.2023 21:43

Question

Химия: 239/93Np-239/94Pu 152/62Sm-148/60Nd 111/46Pd-111/47Ag​

Nightfury1012552 · Accepted Answer

1) Cr -3e- = Cr3+ | 3 | 3 | 1 |

HNO3 +3e- + 3H+ = NO + 2H2O    | 3 |    | 1 |;

Cr + HNO3 + 3H+ = Cr3+ + NO + 2H2O;

Cr + 4HNO3 = Cr(NO3)3 + NO + 2H2O;

2) (MnO4)- +e- = (MnO4)2-    | 1 | 2 | 2 |

(SO3)2- -2e- + 2OH- = (SO4)2- + H2O | 2 |    | 1 |;

2(MnO4)- + (SO3)2- + 2OH- = 2(MnO4)2- + (SO4)2- + H2O;

2KMnO4 + Na2SO3 + 2KOH = 2K2MnO4 + Na2SO4 + H2O;

3) наиболее вероятный вар-т - с учетом окислителя и среды:

U -6e- + 2H2O = (UO2)2+ + 4H+       | 6 | 6 | 1 |

H2O2 +2e- + 2H+ = 2H2O | 2 | | 3 |;

U + 3H2O2 + 2H+ = (UO2)2+ + 4H2O;

U + 3H2O2 + 2HCl = UO2Cl2 + 4H2O.

239/93Np-239/94Pu152/62Sm-148/60Nd111/46Pd-111/47Ag​

MOGZ ответил

239/93Np-239/94Pu
152/62Sm-148/60Nd
111/46Pd-111/47Ag