Сократите дробь 21a^2b^4/7a^4b^5

Question

Математика: Сократите дробь 21a^2b^4/7a^4b^5

4977 · Accepted Answer

25,2 : 3 4/3 + (6 - 4 1/3) * 0,6 = 6 53/65
1) 6 - 4 1/3 = 5 3/3 - 4 1/3 = 1 2/3
2) 25,2 : 3 4/3 = 252/10 : 13/3 = 252/10 * 3/13 = 756/130 = 378/65
3) 1 2/3 * 0,6 = 5/3 * 6/10 = 1
4) 378/65 + 1 = 378/65 + 65/65 = 443/65 = 6 53/65

(7 - 1 5/12) : 6,7 + (5,75 - 3 1/6) : 15,5 = 1
1)7 - 1 5/12 = 6 12/12 - 1 5/12 = 5 7/12
2) 5,75 - 3 1/6 = 575/100 - 19/6 = (3*575 - 50*19)/300 = (1725 - 950)/300 = 775/300 = 31/12
3) 5 7/12 : 6,7 = 67/12 : 67/10 = 67/12 * 10/67 = 5/6
4) 31/12 : 15,5 = 31/12 : 155/10 = 31/12 * 10/155 = 1/6
5) 5/6 + 1/6 = 6/6 = 1

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