Question

Решить уравнение: ((2х)/(2х-+1)/(х+2))=4/(2-3х-2х^2)

Answer 1

2 -3x -2x² = -(2 +x)(2x -1)

(2x(x+2) -(x+1)(2x-1)) /(2x-1)(x+2) = -4/(x+2)(2x-1)

(2x² +4x -(2x² +x -1)) /(x +2)(2x -1) = -4/(x +2)(2x -1)

(2x² +4x -2x² -x +1) /(x +2)(2x -1) = -4/(x+2)(2x -1)

(3x +1)/(x+2)(2x -1) + 4/(x+2)(2x -1) =0
(3x +1 +4) /(x+2)(2x -1) =0
3x +5 =0
3x = -5
x = -5/3
x = -1 2/3(минус одна целая две третьих)