Question

Найти первообразную 1)y=x^3 +1/5x^2 2)y=2/3x-4 3)y=10/x^3+sin(5x-4)

Answer 1

$f{y} = \frac{ {x}^{4} }{4} + \frac{1}{5} \frac{ {x}^{3} }{3} = \frac{ {x}^{4} }{4} + \frac{ {x}^{3} }{15}$
2)
$y = \frac{2}{3} \frac{ {x}^{2} }{2} - 4x = \frac{ {x}^{2} }{3} - 4x$