Question

3. Решите уравнение 3х2-6/ 2(x+1)=х -1

Answer 1

$\frac{3x {}^{2} - 6 }{2(x + 1)} = x - 1$

$\frac{3x {}^{2} - 6}{2(x + 1)} = x - 1$, х ≠ -1

${3x}^{2} - 6 = (x - 1) \times 2(x + 1)$

${3x}^{2} - 6 = ( {x}^{2} - 1) \times 2$

${3x}^{2} - 6 = {2x}^{2} - 2$

${3x}^{2} - {2x}^{2} = - 2 + 6$

${x}^{2} = 4$

х = ± 2

$x = - 2 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: .х ≠ -1 \\ x = 2$

$x = - 2 \\ x = 2$

$x_{1} = - 2 \\ x_{2} = 2$