Question

Решите неравенство а) 1/6x меньше 5 б) 1-3х меньше или равно 0 в) 5(у-1.2)-4.6 больше 3у+1

Answer 1

а)

$\displaystyle \tt \frac{1}{6}x<5\:\:\:\:\:|\cdot6\\\\\displaystyle \tt 6\cdot\frac{1}{6}x<6\cdot5\\\\\displaystyle \tt x<30\\\\\displaystyle \tt \bold{x\in(-\infty; \: 30)}$

б)

$\displaystyle \tt 1-3x\leq 0\\\\\displaystyle \tt -3x\leq -1\\\\\displaystyle \tt x\geq \frac{1}{3}\\\\\displaystyle \tt \bold{x\in [\frac{1}{3}; \: +\infty)}$

в)$\displaystyle \tt 5(y-1,2)-4,63y+1\\\displaystyle \tt 5y-6-4,63y+1\\\displaystyle \tt 5y-10,63y+1\\\displaystyle \tt 5y-3y1+10,6\\\displaystyle \tt 2y11,6\\\displaystyle \tt y11,6\div2\\\displaystyle \tt y5,8\\\\\displaystyle \tt \bold{x\in(5,8; \: +\infty)}$