Выражение. (-5ab/3c )^3 ÷ (-15ac^3/4b^4 )^2 × (3c^2/2b^2 )^5

Question

Алгебра: Выражение. (-5ab/3c )^3 ÷ (-15ac^3/4b^4 )^2 × (3c^2/2b^2 )^5

Мастер008 · Accepted Answer

1)  1 - 16y^2 = 0  - 16y^2 = - 1  16y^2 = 1 y^2 = 1/16 y = ± √(1/16) y = ± 1/4 2) - y^2 + 8 = 0  - y^2 = - 8  y^2 = 8  y = ± √8 y = ± 2√2 3) x^2 - 8x + 15=0 D = 64 - 4*15 = 4 x1 = ( 8 + 2)/2 = 10/2 = 5; x2 = ( 8 - 2)/2 = 6/2 = 3; 4) 2x^2 + 3 x + 1 = 0 D = 9 - 4*2  = 1  x1 = ( - 3 + 1)/4  = - 2/4 = - 1/2; x2 = ( - 3 - 1)/4 = - 4/4 = - 1  наиб  - 1/2 5)  4x^2 - 7x + 3 = 0 D = 49 - 4*4*3 = 49 - 16*3 = 1 x1 = ( 7 + 1)/8 = 1 x2 = ( 7 - 1)/8 = 6/8 = 3/4  6) x^2 - 17x + 42 = 0 D = 289 - 4*42 = 121 x1 =...

MOGZ ответил