Question

Уравнение (x^3-9x^2-x+9)^2+(x^3+3x^2-x-3)^4=0

Answer 1

$(x^3-9x^2-x+9)^2+(x^3+3x^2-x-3)^4=0 \\ (x^2(x-9)-(x-9))^2+((x^2(x+3)-(x+3))^4=0 \\ ((x-1)(x+1)(x-9))^2+((x-1)(x+1)(x+3))^4=0 \\ (x-1)^2(x+1)^2((x-9)^2+(x+3)^2)=0 \\ \\ (x-1)^2=0 \\ x-1=0 \\ x=1 \\ \\ (x+1)^2=0 \\ x+1=0 \\ x=-1 \\ \\ (x-9)^2+(x+3)^2=0 \\ x^2-18x+81+x^2+6x+9=0 \\ 2x^2-12x+90=0 \\ x^2-6x+45=0 \\ D=36-180=-144$
нет решений

ответ: -1; 1