Question

Выражение:

Answer 1

$\frac{8 (y-2)}{y^2 -16} -\frac{y^2}{y^2 -16} =\frac{8 (y-2)-y^2}{y^2 -16} =\frac{ 8y-16-y^{2} }{y^2 -4^{2} }=\\\\=\frac{-(y^{2} -8y+16)}{(y-4)(y+4)} =\frac{-(y-4)^{2} }{(y-4)(y+4)} =\frac{-(y-4)}{y+4} =\frac{4-y}{y+4}$