Question

А)(3x-2)² - (3x-4) (4+3x) =0 б) 25y²-64=0решите уравнение

Answer 1

а) 9x²-12x+4-12x-9x²+16+12x=0

-12x+20=0

-12x=-20

x=5/3

б)(5y-8)(5y+8)=0

5y-8=0, 5y=8, y=8/5

5y+8=0, 5y=-8, y=-8/5

Answer 2

а) (x-2)² - (3x - 4) * (4+3x) = 0

9x² - 12x + 4 - (3x -4) * (3x+4) = 0

9x² - 12x + 4 - (9x² - 16) = 0

9x - 12x + 4 - 9x² + 16 = 0

-12x + 20 = 0

-12x = -20

x = $\frac{5}{3}$

б) 25y² - 64 = 0

-25y² = 64

y = $-\frac{8}{5}$

y = $\frac{8}{5}$

y₁ = $-\frac{8}{5}$,

y₂ = $\frac{8}{5}$