Смотрите.
1) Обозначаем t — сколько времени они шли в первый день, тогда (t-1) — сколько во второй.
2) Теперь следующее соотношение — про 6 километров. Пускай в первый день они км, а во второй день — s2, тогда нам дано:
s1-s2=6.
3) Вспоминая, что расстояние=время*скорость (s=v*t), подставляем в эту формулу вместо s1 и s2:
(3,5*t)-(3*(t-1))=6.
Упрощаем:
3,5t-3t+3=6;
0,5t=3;
t=6.
ответ: Таким образом, в первый день они шли 6 часов. Во второй день — 6-1=5 (часов во второй день — 3*5 = 15 (км)
Пошаговое объяснение:
Пошаговое объяснение:
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Пошаговое объяснение:
3/4 + (2 - 1 11/21) : 4/9 - 1 4/7 = 1/4
2 - 1 11/21 = 2 - 32-21 = (42-32) / 21 = 10/21
10/21 : 4/9 = 10/21 * 9/4 = 15/14
3/4 + 15/14 = (21+30) / 28 = 51/28
51/28 - 1 4/7 = 51/28 - 11/7 = (51-44) / 28 = 7/28 = 1/4