Задание 1.
\tt\displaystyle x=\frac{400+8,5*(-46)}{24,5-(-70)*(-0,25)}=\frac{400-391}{24,5-17,5}=\frac{9}{7}x=
24,5−(−70)∗(−0,25)
400+8,5∗(−46)
=
24,5−17,5
400−391
=
7
9
35% = 35% : 100% = 0,35
\tt\displaystyle 0,35*\frac{9}{7}=\frac{35}{100}*\frac{9}{7}=\frac{35:5}{100:5}*\frac{9}{7}=\frac{7}{20}*\frac{9}{7} =\frac{9}{20}=0,450,35∗
7
9
=
100
35
∗
7
9
=
100:5
35:5
∗
7
9
=
20
7
∗
7
9
=
20
9
=0,45
Задание 2
{47,3:(-11)-4,7}{-23,23:(-0,23)-110} =\frac{-4,3-4,7}{101-110}=\frac{-9}{-9}=1x=
−23,23:(−0,23)−110
47,3:(−11)−4,7
=
101−110
−4,3−4,7
=
−9
−9
=1
12% = 12% : 100% = 0,12
\tt\displaystyle 0,12*1=0,120,12∗1=0,12
ответ: 21.