A) sqrt 5^x=25 b) 9^(x+1)+26*3^(x)-3=0 c) 3^(x+1)-4*3^(x-2)=69 - id207463120210404 от fefe228 04.04.2021 09:53

Question

Алгебра: A) sqrt 5^x=25 b) 9^(x+1)+26*3^(x)-3=0 c) 3^(x+1)-4*3^(x-2)=69

fefe228 · Accepted Answer

1 1*( 2√3 + (√5+3√2))
= =
2√3- (√5+3√2) (2√3- (√5+3√2))*(2√3 +(√5+3√2))

( 2√3 + (√5+3√2)) ( 2√3 + (√5+3√2)) ( 2√3 + (√5+3√2))
= = = =
(2√3)²- (√5+3√2)² 4*2 -(5+2√10+9*2) 8- 23+2√10

( 2√3 + (√5+3√2)) ( 2√3 + (√5+3√2)) * (2√10 + 15)
= = =
2√10 - 15 (2√10 - 15)(2√10 + 15)

( 2√3 + √5+ 3√2) * (2√10 + 15) ( 2√3 + √5+ 3√2) * (2√10 + 15)
= =
4*10- 15² -185

A) sqrt 5^x=25 b) 9^(x+1)+263^(x)-3=0 c) 3^(x+1)-43^(x-2)=69

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