Question

Разложите многочлен на множетели. 9n^2-m^2*n^2-m^2+9 ^ возведение в степень

Answer 1

$9 n^{2}-m ^{2}n ^{2} -m ^{2} +9=9n ^{2}+9-m ^{2} n ^{2}-m ^{2}= \\ 9( n^{2} +1)-m ^{2}(n ^{2} +1)=(9-m ^{2})(n ^{2} +1)=(3-m)(3+m)(n ^{2}+1)$

Answer 2

9n²-m²n²-m²+9=9n²+9-m²n²-m²=9(n²+1)-m²(n²+1)=(n²+1)(9-m²)