Question

Найдите производную функции y=x^2 / 2x+4

Answer 1

$y= \frac{x^2}{2x+4} \\ \\ y'= \frac{(x^2)'(2x+4)-(2x+4)'x^2}{(2x+4)^2} = \frac{2x(2x+4)-2x^2}{(2x+4)^2} = \frac{4x^2+8x-2x^2}{(2x+4)^2} = \frac{2x^2+8x}{(2x+4)^2} = \\ =\frac{2(x^2+4x)}{(2(x+2))^2} = \frac{2(x^2+4x)}{4(x+2)^2 } = \frac{x^2+4x}{2(x+2)^2}$