Question

Решите уравнения. . а) х(х+1)(х-10)=(х-1)(х-3)(х-5) б) (х-1)(х-4)(х+7)=х(х+1) во второй степени

Answer 1

Б)
$(x {}^{2} - 4x - x + 4)(x + 7) = x(x {}^{2} + 2x + 1)$
$(x {}^{2} - 5x + 4)(x + 7) = x {}^{3} + 2x {}^{2} + x$
$x {}^{3} + 7x {}^{2} - 5x {}^{2} - 35x + 4x + 28 = x {}^{3} + 2x {}^{2} + x$
$7x {}^{2} - 5x {}^{2} - 35x + 4x + 28 = 2x {}^{2} + x$
$2x {}^{2} - 31x + 28 = 2x {}^{2} + x$
$- 31x + 28 = x$
$- 31x - x = - 28$
$- 32x = - 28$
$x = \frac{7}{8}$